Hacker rank Challenges #006

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 Task

For each integer  in the interval  (given as input) :

  • If , then print the English representation of it in lowercase. That is "one" for , "two" for , and so on.
  • Else if  and it is an even number, then print "even".
  • Else if  and it is an odd number, then print "odd".

Input Format

The first line contains an integer, .
The seond line contains an integer, .

Constraints

Output Format

Print the appropriate English representation,even, or odd, based on the conditions described in the 'task' section.

Note: 

Sample Input

8
11

Sample Output

eight
nine
even
odd

Source Code :

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

void cal(n){
    if (n==1){
        printf("one");
    }else if (n==2){
        printf("two");
    }else if (n==3){
        printf("three");
    }else if (n==4){
        printf("four");
    }else if (n==5){
        printf("five");
    }else if (n==6){
        printf("six");
    }else if (n==7){
        printf("seven");
    }else if (n==8){
        printf("eight");
    }else if (n==9){
        printf("nine");
    }else if (n%2 ==0){
        printf("even");
    }else{
        printf("odd");
    }

}


int main() 
{
    int a, b,i;
    scanf("%d\n%d", &a, &b);
    // Complete the code.
    if (a>=b){
        for (i=0;i<=a-b;i++){
            cal(a+i);
            printf("\n");
        }
    }
    else{
        for (i=0;i<=b-a;i++){
            cal(a+i);
            printf("\n");
            
        }
    }
    return 0;
}



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